4x^2-8x+5=0

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Solution for 4x^2-8x+5=0 equation:


Simplifying
4x2 + -8x + 5 = 0

Reorder the terms:
5 + -8x + 4x2 = 0

Solving
5 + -8x + 4x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
4 the coefficient of the squared term: 

Divide each side by '4'.
1.25 + -2x + x2 = 0

Move the constant term to the right:

Add '-1.25' to each side of the equation.
1.25 + -2x + -1.25 + x2 = 0 + -1.25

Reorder the terms:
1.25 + -1.25 + -2x + x2 = 0 + -1.25

Combine like terms: 1.25 + -1.25 = 0.00
0.00 + -2x + x2 = 0 + -1.25
-2x + x2 = 0 + -1.25

Combine like terms: 0 + -1.25 = -1.25
-2x + x2 = -1.25

The x term is -2x.  Take half its coefficient (-1).
Square it (1) and add it to both sides.

Add '1' to each side of the equation.
-2x + 1 + x2 = -1.25 + 1

Reorder the terms:
1 + -2x + x2 = -1.25 + 1

Combine like terms: -1.25 + 1 = -0.25
1 + -2x + x2 = -0.25

Factor a perfect square on the left side:
(x + -1)(x + -1) = -0.25

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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